36x+x^2=2(x^2)

Solution for 36x+x^2=2(x^2) equation:

36x+x^2=2(x^2)

We move all terms to the left:

36x+x^2-(2(x^2))=0

determiningTheFunctionDomain
x^2+36x-2x^2=0

We add all the numbers together, and all the variables

x^2-2x^2+36x=0

We add all the numbers together, and all the variables

-1x^2+36x=0

a = -1; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-1)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-1}=\frac{-72}{-2}
=+36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-1}=\frac{0}{-2}
=0
$